document.write( "Question 824332: Express the ratio of the area of the larger circle to the area of the smaller circle in simplest radical form.
\n" ); document.write( "Radius of larger circle is 2 + sqrt of 3
\n" ); document.write( "Radius of smaller circle is 2 - sqrt of 3\r
\n" ); document.write( "\n" ); document.write( "Advance Thanks to whoever answers :)
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Algebra.Com's Answer #496338 by jsmallt9(3759)\"\" \"About 
You can put this solution on YOUR website!
The formula for area of a circle is:
\n" ); document.write( "\"A+=+pi%2Ar%5E2\"
\n" ); document.write( "So the area for the larger circle will be:
\n" ); document.write( "\"A%5BL%5D+=+pi%2A%282%2Bsqrt%283%29%29%5E2\"
\n" ); document.write( "Using the \"%28a%2Bb%29%5E2+=+a%5E2%2B2ab%2Bb%5E2\" pattern to square the radius:
\n" ); document.write( "\"A%5BL%5D+=+pi%2A%28%282%29%5E2%2B2%282%29%28sqrt%283%29%29%2B%28sqrt%283%29%29%5E2%29\"
\n" ); document.write( "Simplifying...
\n" ); document.write( "\"A%5BL%5D+=+pi%2A%284%2B4sqrt%283%29%2B3%29\"
\n" ); document.write( "\"A%5BL%5D+=+pi%2A%287%2B4sqrt%283%29%29\"

\n" ); document.write( "Repeating this for the smaller circle:
\n" ); document.write( "\"A%5BS%5D+=+pi%2A%282-sqrt%283%29%29%5E2\"
\n" ); document.write( "Using the \"%28a-b%29%5E2+=+a%5E2-2ab%2Bb%5E2\" pattern to square the radius:
\n" ); document.write( "\"A%5BS%5D+=+pi%2A%28%282%29%5E2-2%282%29%28sqrt%283%29%29%2B%28sqrt%283%29%29%5E2%29\"
\n" ); document.write( "Simplifying...
\n" ); document.write( "\"A%5BS%5D+=+pi%2A%284-4sqrt%283%29%2B3%29\"
\n" ); document.write( "\"A%5BS%5D+=+pi%2A%287-4sqrt%283%29%29\"

\n" ); document.write( "Now we find the ratio of these areas:
\n" ); document.write( "\"A%5BL%5D%2FA%5BS%5D+=+%28pi%2A%287%2B4sqrt%283%29%29%29%2F%28pi%2A%287-4sqrt%283%29%29%29\"
\n" ); document.write( "Simplifying... The \"pi\"'s cancel:
\n" ); document.write( "\"A%5BL%5D%2FA%5BS%5D+=+%287%2B4sqrt%283%29%29%2F%287-4sqrt%283%29%29\"
\n" ); document.write( "This may be an acceptable answer.

\n" ); document.write( "But it does have a square root in the denominator. Usually denominators should be rationalized:
\n" ); document.write( "
\n" ); document.write( "Using the \"%28a%2Bb%29%5E2\" pattern on top and the \"%28a%2Bb%29%28a-b%29=a%5E2-b%5E2\" pattern on the bottom:
\n" ); document.write( "
\n" ); document.write( "Simplifying...
\n" ); document.write( "\"A%5BL%5D%2FA%5BS%5D+=+%2849%2B56sqrt%283%29%2B48%29%2F%2849-48%29\"
\n" ); document.write( "\"A%5BL%5D%2FA%5BS%5D+=+%2897%2B56sqrt%283%29%29%2F1\"
\n" ); document.write( "\"A%5BL%5D%2FA%5BS%5D+=+97%2B56sqrt%283%29\"
\n" ); document.write( "
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