document.write( "Question 824317: Using the given information, find the expected value. X = 0, 1, 2, 4, 6 and the respective probabilities are .1, .2, ?, .3, .3
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Algebra.Com's Answer #496300 by Edwin McCravy(20077)\"\" \"About 
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document.write( "X    P(X)\r\n" );
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document.write( "0    .1\r\n" );
document.write( "1    .2 \r\n" );
document.write( "2     ?\r\n" );
document.write( "4    .3\r\n" );
document.write( "6    .3\r\n" );
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document.write( "For this to be a probability distribution, the sum\r\n" );
document.write( "of the probabilities must = 1.  So since the probability\r\n" );
document.write( "of the other four values of X have sum\r\n" );
document.write( ".1+.2+.3+.3 = .9, then P(2) = 1.0-.9 = .1 and the\r\n" );
document.write( "distribution is:\r\n" );
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document.write( "X    P(X)     E(X)=X·P(X)\r\n" );
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document.write( "0    .1            0    \r\n" );
document.write( "1    .2           .2\r\n" );
document.write( "2    .1           .2\r\n" );
document.write( "4    .3          1.2\r\n" );
document.write( "6    .3          1.8\r\n" );
document.write( "--------------------------   \r\n" );
document.write( "Sum = 1  ∑E(X) = 3.4\r\n" );
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document.write( "Answer:  ∑E(X) = 3.4 \r\n" );
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document.write( "Edwin

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