document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=824305>Question 824305</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi,<BR>\n" );
document.write( "I have Problem with the following question<BR>\n" );
document.write( "Question - two tanks contain equal amounts of water. they are connected by a pipe and 3000 litres of water is pumped from one tank to the other. one tank then contains 6 times as much water as the other. how many litres of water did each tank contain originally?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #496261 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=496261\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the tanks A and B.  Originally A=B.  Say the water was pumped from A to B.<P><BR>\n" );
document.write( "That means subtract 3000 liters from A (A-3000) and add 3000 liters to B (B+3000).  B+3000 is 6 times A-3000.<P><BR>\n" );
document.write( "6(A-3000) = B+3000 ---> 6A - 18000 = B + 3000.<P><BR>\n" );
document.write( "Remember, that A = B.  So substitute B into the equation for A.<P><BR>\n" );
document.write( "6B - 18000 = B + 3000<P><BR>\n" );
document.write( "5B = 21000<P><BR>\n" );
document.write( "B = 21000/5 = 4200 = A.<P><BR>\n" );
document.write( "Both tanks originally held 4200 liters.  After 3000 liters were pumped from A to B:<P><BR>\n" );
document.write( "A held 1200 and B held 7200.  6*1200 = 7200 </SPAN>\n" );
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