document.write( "Question 824218: A train leaves the station traveling west at a constant rate of 45 mph. An express train leaves the same station 1 hour later heading west on the same route, traveling at a constant rate of 60 mph. How many hours will the first train have been traveling when the express train catches up to it? \n" ); document.write( "
Algebra.Com's Answer #496185 by TimothyLamb(4379)\"\" \"About 
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\n" ); document.write( "head start trainA:
\n" ); document.write( "s = d / t
\n" ); document.write( "d = s * t
\n" ); document.write( "d = 45 * 1
\n" ); document.write( "d = 45 miles
\n" ); document.write( "---
\n" ); document.write( "relative speed:
\n" ); document.write( "60 - 45 = 15 mph
\n" ); document.write( "---
\n" ); document.write( "time to the meeting, after trainB departs:
\n" ); document.write( "t = d / s
\n" ); document.write( "t = 45/15
\n" ); document.write( "t = 3
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "trainA will have been traveling 4 hours when trainB catches up
\n" ); document.write( "---
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