document.write( "Question 824198: Approximately 70% of U.S. adults had at least one pet as a child. We randomly survey 60 U. S. adults. We are interested in the number that had at least one pet as a child. The probability that at least 3 adults had at least one pet as a child means:\r
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document.write( "A. P(X=0)+P(X=1)+P(X=2)+P(X=3)
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document.write( "B. P(X=0)+P(X=1)+P(X=2)
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document.write( "C. P(X=4)+P(X=5)+P(X=6)+ ...
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document.write( "D. P(X=3)+P(X=4)+P(X=5)+ ...
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Algebra.Com's Answer #496171 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Approximately 70% of U.S. adults had at least one pet as a child. We randomly survey 60 U. S. adults. We are interested in the number that had at least one pet as a child. The probability that at least 3 adults had at least one pet as a child means: \n" ); document.write( "A. P(X=0)+P(X=1)+P(X=2)+P(X=3) \n" ); document.write( "B. P(X=0)+P(X=1)+P(X=2) \n" ); document.write( "C. P(X=4)+P(X=5)+P(X=6)+ ... \n" ); document.write( "D. P(X=3)+P(X=4)+P(X=5)+ ... \n" ); document.write( "------------------ \n" ); document.write( "Answer: D \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |