document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=69685>Question 69685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tell the answer to, or how to put, 4x-5y=10 -into slope intercept form<BR>\n" );
document.write( "Tell the answer to, or how to put, y=-3/2x+4 -into standard form </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49617 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49617\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tell the answer to, or how to put, y=-3/2x+4 -into standard form\r<BR>\n" );
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document.write( "The slope-intercept form is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+mx+%2B+b ALIGN=MIDDLE  ALT=\"y+=+mx+%2B+b\"   DISABLED_style= \"max-width:90%; height:auto;\" > in which m and b are constants, in which m is the slope of the graph and b is the value where the graph intercepts the y-axis.\r<BR>\n" );
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document.write( "So what you need to do for the first problem is to move the terms around and solve for y to get the equation to match the slope intercept form.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x+-+5y+=+10 ALIGN=MIDDLE  ALT=\"4x+-+5y+=+10\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Move the 4x term to the right side of the equation, by subtracting 4x from both sides.  This subtraction cancels out the 4x on the left side and makes a -4x appear on the right side as follows:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=++-5y+=+-4x+%2B+10 ALIGN=MIDDLE  ALT=\"++-5y+=+-4x+%2B+10\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now divide all terms on both sides of the equal sign by -5 to get:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%28-4%2F-5%29x+%2B+10%2F-5 ALIGN=MIDDLE  ALT=\"y+=+%28-4%2F-5%29x+%2B+10%2F-5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "When you divide -4 by -5 the answer becomes positive.  And dividing +10 by -5 results in -2.  So the answer becomes:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y++=+%284%2F5%29x+-+2 ALIGN=MIDDLE  ALT=\"y++=+%284%2F5%29x+-+2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The next problem involves putting an equation into standard form.  The standard form is:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ax+%2B+by+=+c ALIGN=MIDDLE  ALT=\"ax+%2B+by+=+c\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "where a, b, and c are all constants.  So what you need to do is take the equation you are given, an equation in slope-intercept form, and rearrange things to get it into standard form.  You are given:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%28-3%2F2%29x%2B4 ALIGN=MIDDLE  ALT=\"y+=+%28-3%2F2%29x%2B4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Get rid of the denominator of 2 by multiplying all the terms in this equation by 2 to get:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y+=+-3x+%2B+8 ALIGN=MIDDLE  ALT=\"2y+=+-3x+%2B+8\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Next, move the -3x term to the other side of the equal sign by adding 3x to both sides.  Adding +3x to the right side cancels the -3x. And adding 3x on the left side makes a +3x appear on the left side.  The result is:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2B3x+%2B+2y+=+8 ALIGN=MIDDLE  ALT=\"%2B3x+%2B+2y+=+8\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "This is the standard form that you are looking for.\r<BR>\n" );
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document.write( "Hope this helps. </SPAN>\n" );
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