document.write( "Question 824192: Hi. I have a solution to this problem, yet doesn't seem ok: \r
\n" ); document.write( "\n" ); document.write( "One tract can be ploughed with 6 tractors for 4 days, if they plough 120hectares a day. Two of the tractors were moved to another tract. The rest 4 ploughed the same tract for 5 days. How many decares average a day ploughed the 4 tractors? \r
\n" ); document.write( "\n" ); document.write( "Thanx for the help.
\n" ); document.write( "

Algebra.Com's Answer #496157 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
For 6 tractors, their rate of ploughing the tract is
\n" ); document.write( "\"+120%2F4+=+30+\" hectares/day
\n" ); document.write( "----------------------------
\n" ); document.write( "1/6 as many tractors will plough the tract at
\n" ); document.write( "1/6 times that rate, so
\n" ); document.write( "--------------------
\n" ); document.write( "1 tractor will plow 1 tract in at a rate of \"+30%2F6+=+5+\"
\n" ); document.write( "hectares/day
\n" ); document.write( "--------------
\n" ); document.write( "4 tractors will plough at 4 times that rate, so
\n" ); document.write( "--------------
\n" ); document.write( "4 tractors will plow 1 tract in at a rate of \"+4%2A5+=+20+\"
\n" ); document.write( "hectares/day
\n" ); document.write( "--------------
\n" ); document.write( "If the 4 tractors plough for 5 days, they will plough
\n" ); document.write( "\"+20%2A5+=+100+\" hectares
\n" ); document.write( "--------------
\n" ); document.write( "Hope I got it
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );