document.write( "Question 587199: If a father is now 5 times as old as his son, how many years ago was the son 2 years old and the father 34 years old?\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #496146 by TamiSrcKa(4)\"\" \"About 
You can put this solution on YOUR website!
now
\n" ); document.write( "father 5x
\n" ); document.write( "son x
\n" ); document.write( ".....
\n" ); document.write( "before
\n" ); document.write( "father 34
\n" ); document.write( "son 2\r
\n" ); document.write( "\n" ); document.write( "_________________
\n" ); document.write( "Easiest solution:\r
\n" ); document.write( "\n" ); document.write( "34-2=5x-x
\n" ); document.write( "32=4x
\n" ); document.write( "x=32/4
\n" ); document.write( "x=8\r
\n" ); document.write( "\n" ); document.write( ">>> The father is 5x=5*8=40, and the son is 8. > (f)now-(f)before=40-34=6
\n" ); document.write( "The father was 34 and the son was 2, 6 years ago.
\n" ); document.write( "
\n" );