document.write( "Question 69672: please help solve the equation...Jill has $3.50 in nickels and dimes..if she has 50 coins, how many of each type of coin does she have?\r
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document.write( "X= nickels = .05
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document.write( "Y= dimes = .10\r
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document.write( ".05X + .10Y = 50\r
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Algebra.Com's Answer #49614 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "AT LEAST YOU ARE GIVING IT A SHOT!!!!!!\r \n" ); document.write( "\n" ); document.write( "BUT SEE WHAT YOU THINK ABOUT THIS APPROACH:\r \n" ); document.write( "\n" ); document.write( "Let x= number of nickels \n" ); document.write( "Then 50-x=number of dimes\r \n" ); document.write( "\n" ); document.write( "NOW LETS START DEALING IN PENNIES TO KEEP DOWN CONFUSION:\r \n" ); document.write( "\n" ); document.write( "Now we are told that the amount of money in nickels (5x) plus the amount of money in dimes (10(50-x)) equals 350 (pennies). So our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "5x+10(50-x)=350 get rid of parens\r \n" ); document.write( "\n" ); document.write( "5x+500-10x=350 subtract 500 from both sides \n" ); document.write( "-5x=-500+350 \n" ); document.write( "-5x=-150 \n" ); document.write( "x=30-------------------------number of nickels\r \n" ); document.write( "\n" ); document.write( "50-x=50-30=20----------------------number of dimes\r \n" ); document.write( "\n" ); document.write( "Ck\r \n" ); document.write( "\n" ); document.write( "30(5)+20(10)=350 \n" ); document.write( "150+200=350 \n" ); document.write( "350=350\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |