document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=824115>Question 824115</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a football field is 180 feet more than its width. if the perimeter of the field is 1,060 feet ,find the length of the field. show your work </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #496095 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=496095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a football field is 180 feet more than its width. if the perimeter of the field is 1,060 feet ,find the length of the field. <BR>\n" );
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document.write( "Perimeter = 2(length + width)<BR>\n" );
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document.write( "1060 = 2((w+180)+w)<BR>\n" );
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document.write( "530 = 2w+180<BR>\n" );
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document.write( "2w = 350<BR>\n" );
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document.write( "width = 175 feet<BR>\n" );
document.write( "length = w+180 = 175+180 = 355 feet<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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