document.write( "Question 824100: John had $ 30,000 to invest. He invested part of this money in bonds paying 12% annual simple interest and the rest of the money in savings account giving 4% annual interest. At the end of the year, he received $2,400 as extra income. How much money did John place in each investment? \n" ); document.write( "
Algebra.Com's Answer #496082 by framos119(1)\"\" \"About 
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.4x+.12(30000-x)=2400
\n" ); document.write( ".04x+.12(30000)-.12x=2400
\n" ); document.write( ".04x+3600-.12x=2400
\n" ); document.write( ".12x-.04x+3600=2400
\n" ); document.write( ".08x+3600=2400
\n" ); document.write( ".08x+3600-3600=2400-3600
\n" ); document.write( "8x=1200
\n" ); document.write( "(8x/8)=1200/8
\n" ); document.write( "X=1500
\n" ); document.write( "15000-30000=15000
\n" ); document.write( "Total invested at .12=$15,000.00
\n" ); document.write( " At .04=$15,000.00
\n" ); document.write( "15000*.04=$600.00
\n" ); document.write( "15000*.12=$1,800.00
\n" ); document.write( "$1,800.00+$600.00=$2,400.00
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