document.write( "Question 824100: John had $ 30,000 to invest. He invested part of this money in bonds paying 12% annual simple interest and the rest of the money in savings account giving 4% annual interest. At the end of the year, he received $2,400 as extra income. How much money did John place in each investment? \n" ); document.write( "
Algebra.Com's Answer #496082 by framos119(1)![]() ![]() You can put this solution on YOUR website! .4x+.12(30000-x)=2400 \n" ); document.write( ".04x+.12(30000)-.12x=2400 \n" ); document.write( ".04x+3600-.12x=2400 \n" ); document.write( ".12x-.04x+3600=2400 \n" ); document.write( ".08x+3600=2400 \n" ); document.write( ".08x+3600-3600=2400-3600 \n" ); document.write( "8x=1200 \n" ); document.write( "(8x/8)=1200/8 \n" ); document.write( "X=1500 \n" ); document.write( "15000-30000=15000 \n" ); document.write( "Total invested at .12=$15,000.00 \n" ); document.write( " At .04=$15,000.00 \n" ); document.write( "15000*.04=$600.00 \n" ); document.write( "15000*.12=$1,800.00 \n" ); document.write( "$1,800.00+$600.00=$2,400.00 \n" ); document.write( " \n" ); document.write( " |