document.write( "Question 824066: решить уравнения:
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document.write( "3sinˆx+sinx*cosx=2cosˆx
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document.write( "4sinx-sin2x=3 \n" );
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Algebra.Com's Answer #496070 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( " 3sin²(x) + sin(x)cos(x) = 2cos²(x), 0° < x < 360°\r\n" ); document.write( "\r\n" ); document.write( " Вычтите 2cos²(x) с обеих сторон. Получите ноль справа.\r\n" ); document.write( "\r\n" ); document.write( " 3sin²(x) + sin(x)cos(x) - 2cos²(x) = 0\r\n" ); document.write( "\r\n" ); document.write( " Фактор как ab-2b² + 3a² = (a+b)(3a-2b)\r\n" ); document.write( "\r\n" ); document.write( "[sin(x) + cos(x)][3sin(x) - 2cos(x)] = 0\r\n" ); document.write( "\r\n" ); document.write( " Используйте свойство zero фактор\r\n" ); document.write( "\r\n" ); document.write( "sin(x) + cos(x) = 0 3sin(x) - 2cos(x) = 0\r\n" ); document.write( "\r\n" ); document.write( " Разделите каждый термин cos(x)\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |