document.write( "Question 824043: I need mire detail solution (and explanation what formulas should be used):\r
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document.write( "A Nintendo DS costs one hundred and twenty British pounds sterling (£120). I decide today, 17th
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document.write( "April 2013, to put 10p aside. Tomorrow I’ll put 15p, the day after 20p, the day after that 25p and
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document.write( "so on, increasing the amount by 5p every day. At which date will I have enough to buy the
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document.write( "Nintendo?
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document.write( "£1 = one pound = 100 pennies = 100p \n" );
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Algebra.Com's Answer #496040 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A Nintendo DS costs one hundred and twenty British pounds sterling (£120). I decide today, 17th April 2013, to put 10p aside. Tomorrow I’ll put 15p, the day after 20p, the day after that 25p and \n" ); document.write( "so on, increasing the amount by 5p every day. At which date will I have enough to buy the \n" ); document.write( "Nintendo? \n" ); document.write( "£1 = one pound = 100 pennies = 100p \n" ); document.write( "------- \n" ); document.write( "Series: 10 + 15 + 20 + 25 + ... \n" ); document.write( "---- \n" ); document.write( "Arithmetic Series with a = 10 and d = 5 \n" ); document.write( "----- \n" ); document.write( "Formula: S(n) = (n/2)(A + L) \n" ); document.write( "L = A + (n-1)d \n" ); document.write( "---- \n" ); document.write( "A = 10 \n" ); document.write( "d = 5 \n" ); document.write( "S(n) >= 120 \n" ); document.write( "---- \n" ); document.write( "120 =< (n/2)(10+L) \n" ); document.write( "240 =< n(10+(A+(n-1)5) \n" ); document.write( "240 =< n(10 + 10+(n-1)5) \n" ); document.write( "240 =< n(20 + 5n-5) \n" ); document.write( "240 =< n(15 + 5n) \n" ); document.write( "48 =< n(3+n) \n" ); document.write( "n^2 + 3n - 48 >= 0 \n" ); document.write( "n = >= 6 \n" ); document.write( "----- \n" ); document.write( "Answer:: 17th + 6 = 23rd \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |