document.write( "Question 824043: I need mire detail solution (and explanation what formulas should be used):\r
\n" ); document.write( "\n" ); document.write( "A Nintendo DS costs one hundred and twenty British pounds sterling (£120). I decide today, 17th
\n" ); document.write( "April 2013, to put 10p aside. Tomorrow I’ll put 15p, the day after 20p, the day after that 25p and
\n" ); document.write( "so on, increasing the amount by 5p every day. At which date will I have enough to buy the
\n" ); document.write( "Nintendo?
\n" ); document.write( "£1 = one pound = 100 pennies = 100p
\n" ); document.write( "

Algebra.Com's Answer #496040 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A Nintendo DS costs one hundred and twenty British pounds sterling (£120). I decide today, 17th April 2013, to put 10p aside. Tomorrow I’ll put 15p, the day after 20p, the day after that 25p and
\n" ); document.write( "so on, increasing the amount by 5p every day. At which date will I have enough to buy the
\n" ); document.write( "Nintendo?
\n" ); document.write( "£1 = one pound = 100 pennies = 100p
\n" ); document.write( "-------
\n" ); document.write( "Series: 10 + 15 + 20 + 25 + ...
\n" ); document.write( "----
\n" ); document.write( "Arithmetic Series with a = 10 and d = 5
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\n" ); document.write( "Formula: S(n) = (n/2)(A + L)
\n" ); document.write( "L = A + (n-1)d
\n" ); document.write( "----
\n" ); document.write( "A = 10
\n" ); document.write( "d = 5
\n" ); document.write( "S(n) >= 120
\n" ); document.write( "----
\n" ); document.write( "120 =< (n/2)(10+L)
\n" ); document.write( "240 =< n(10+(A+(n-1)5)
\n" ); document.write( "240 =< n(10 + 10+(n-1)5)
\n" ); document.write( "240 =< n(20 + 5n-5)
\n" ); document.write( "240 =< n(15 + 5n)
\n" ); document.write( "48 =< n(3+n)
\n" ); document.write( "n^2 + 3n - 48 >= 0
\n" ); document.write( "n = >= 6
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\n" ); document.write( "Answer:: 17th + 6 = 23rd
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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