document.write( "Question 823877: ABCD IS A PARALLELOGRAM.TRIANGLE DEC IS DRAWN SUCH THAT BE=1/3 AE.SUM OF THE AREAS OF TRIANGLES ADE AND BEC IS? \n" ); document.write( "
Algebra.Com's Answer #496016 by KMST(5345) You can put this solution on YOUR website! Since the problem does not state any side measurements (just a ratio), the most that we could do is calculate that sum of areas relative to the area of the parallelogram. \n" ); document.write( "Without a picture, I am not quite sure I can interpret the situation intended, but I will try. \n" ); document.write( " \n" ); document.write( "We could calculate that sum of areas as \n" ); document.write( " \n" ); document.write( "In that case, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "area of ADE + area of BCE = \n" ); document.write( "area of ADE + area of BCE = \n" ); document.write( "area of ADE + area of BCE = \n" ); document.write( "It really does not matter what fraction of AE is BE, \n" ); document.write( "because the heights of ADE and BCE would add up to \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It really does not matter where E is located, as long as it is between the lines AD and BC, \n" ); document.write( " \n" ); document.write( "based on \n" ); document.write( "and the distances from E to AB and to BC as the heights. \n" ); document.write( "And those heights would add up to \n" ); document.write( "The ratio of AE is BE, does not matter either, \n" ); document.write( "because the heights of ADE and BCE would add up to |