document.write( "Question 824010: Three times the sum of the digits of a positive, two-digit integer is 50 greater than the difference of the digits. Reversing the digits decreases the number by 9. What is the number? \n" ); document.write( "
Algebra.Com's Answer #496012 by lwsshak3(11628)\"\" \"About 
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Three times the sum of the digits of a positive, two-digit integer is 50 greater than the difference of the digits. Reversing the digits decreases the number by 9. What is the number?
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\n" ); document.write( "let u=units digit
\n" ); document.write( "let t=tens digit
\n" ); document.write( "..
\n" ); document.write( "3(t+u)-(t-u)=50
\n" ); document.write( "(10t+u)-(10u+t)=9
\n" ); document.write( "..
\n" ); document.write( "3t+3u-t+u=50
\n" ); document.write( "10t+u-10u-t=9
\n" ); document.write( "..
\n" ); document.write( "2t+4u=50
\n" ); document.write( "9t-9u=9
\n" ); document.write( "..
\n" ); document.write( "18t+36u=450
\n" ); document.write( "36t-36u=36
\n" ); document.write( "add:
\n" ); document.write( "54t=486
\n" ); document.write( "t=9
\n" ); document.write( "4u=50-2t=50-18=32
\n" ); document.write( "u=8
\n" ); document.write( "What is the number? 98
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