document.write( "Question 823978: Hello,
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Algebra.Com's Answer #495965 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Because ABC is a circumscribed triangle, this means that AB, BC, and AC are tangents to the circle. Therefore, with a bit of proof (which we don't need to do really unless you want to), we can show the following is true\r
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\n" ); document.write( "\n" ); document.write( "AP = AR
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\n" ); document.write( "CQ = CR\r
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\n" ); document.write( "\n" ); document.write( "We are given AR = 10, CQ = 8, BQ = 4, so...\r
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\n" ); document.write( "\n" ); document.write( "AP = AR
\n" ); document.write( "BP = BQ
\n" ); document.write( "CQ = CR\r
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\n" ); document.write( "\n" ); document.write( "turns into\r
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\n" ); document.write( "\n" ); document.write( "AP = 10
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\n" ); document.write( "8 = CR\r
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\n" ); document.write( "\n" ); document.write( "which rearranges to\r
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\n" ); document.write( "\n" ); document.write( "AP = 10
\n" ); document.write( "BP = 4
\n" ); document.write( "CR = 8\r
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\n" ); document.write( "\n" ); document.write( "Then we use the segment addition postulate\r
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\n" ); document.write( "\n" ); document.write( "AB = AP + PB\r
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\n" ); document.write( "\n" ); document.write( "AB = AP + BP\r
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\n" ); document.write( "\n" ); document.write( "AB = 10 + 4\r
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\n" ); document.write( "\n" ); document.write( "AB = 14 units
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