document.write( "Question 823899: one leg of a right triangle is 3 millimeters shorter than the longer leg and the hypotenuse is 3 millimeters longer than the longer leg. find the lengths of the sides of the triangle.\r
\n" ); document.write( "\n" ); document.write( "The length of the longer leg is? millimeters\r
\n" ); document.write( "\n" ); document.write( "The length of the shorter leg is? millimeters\r
\n" ); document.write( "\n" ); document.write( "The length of the hypotenuse is? millimeters
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Algebra.Com's Answer #495909 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
let legs be \"a\" and \"b\", and the hypotenuse \"c\"\r
\n" ); document.write( "\n" ); document.write( "let shorter leg be \"a=x\"\r
\n" ); document.write( "\n" ); document.write( "then the longer leg is \"b=a%2B3\" or \"b=x%2B3\" \r
\n" ); document.write( "\n" ); document.write( "if the hypotenuse \"c\" is \"3\" millimeters longer than the longer leg \"b\", then \"c=b%2B3\".....substitute \"b=x%2B3\" and you have \"c=x%2B3%2B3=x%2B6\"\r
\n" ); document.write( "\n" ); document.write( "use Pythagorean theorem:\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=a%5E2%2Bb%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B6%29%5E2=x%5E2%2B%28x%2B3%29%5E2\"................solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B12x%2B36=x%5E2%2Bx%5E2%2B6x%2B9\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B12x%2B36=2x%5E2%2B6x%2B9\"\r
\n" ); document.write( "\n" ); document.write( "\"0=2x%5E2%2B6x%2B9-x%5E2-12x-36\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-6x-27=0\"............write \"-6x\" as \"-9x%2B3x\" \r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-9x%2B3x-27=0\"............group\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-9x%29%2B%283x-27%29=0\"............factor out \"x\" and \"3\"\r
\n" ); document.write( "\n" ); document.write( "\"x%28x-9%29%2B3%28x-9%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B3%29%28x-9%29=0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if \"%28x%2B3%29=0\" => \"x=-3\"...........leg cannot be negative length, so disregard this solution\r
\n" ); document.write( "\n" ); document.write( "if \"%28x-9%29=0\"=> \"x=9\"..............your solution; now use it to find out the length of legs and hypotenuse\r
\n" ); document.write( "\n" ); document.write( "\"a=x\"=>\"a=9\"\r
\n" ); document.write( "\n" ); document.write( "\"b=x%2B3\" =>\"b=9%2B3\" =>\"b=12\" \r
\n" ); document.write( "\n" ); document.write( "\"c=x%2B6\"=>\"c=9%2B6\"=>\"c=15\"\r
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\n" ); document.write( "\n" ); document.write( "check our solution:\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=a%5E2%2Bb%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"15%5E2=9%5E2%2B12%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"225=81%2B144\"\r
\n" ); document.write( "\n" ); document.write( "\"225=225\"\r
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