document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=823842>Question 823842</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diagonal of a rectangle is 15 inches and the area is 50 square inches. Find the dimensions of the rectangle, correct to one decimal place. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #495898 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39630)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=495898\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "The diagonal creates two triangles, each with legs x and y.  Pythagorean theorem relationship gives <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28x%5E2%2By%5E2=15%5E2%29 ALIGN=MIDDLE  ALT=\"highlight_green%28x%5E2%2By%5E2=15%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, because the diagonal also becomes the hypotenuse of the two triangles.\r<BR>\n" );
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document.write( "The given area permits the equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28xy=50%29 ALIGN=MIDDLE  ALT=\"highlight_green%28xy=50%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Various ways to continue, but take the area equation and solve for either x or y; substitute into the pythagorean theorem equation and solve for the present variable; and then solve for the other using the area xy equation.\r<BR>\n" );
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document.write( "To start, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=50%2Fx ALIGN=MIDDLE  ALT=\"y=50%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" >;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B%2850%2Fx%29%5E2=15%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2B%2850%2Fx%29%5E2=15%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B2500%2F%28x%5E2%29-15%5E2=0 ALIGN=MIDDLE  ALT=\"x%5E2%2B2500%2F%28x%5E2%29-15%5E2=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "You WILL need to deal with solving for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2 ALIGN=MIDDLE  ALT=\"x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > first!<BR>\n" );
document.write( "Multiplying left and right by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2 ALIGN=MIDDLE  ALT=\"x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E4%2B2500-15%5E2%2Ax%5E2=0 ALIGN=MIDDLE  ALT=\"x%5E4%2B2500-15%5E2%2Ax%5E2=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E4-225x%5E2%2B2500=0 ALIGN=MIDDLE  ALT=\"x%5E4-225x%5E2%2B2500=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=%28225%2Bsqrt%28225%5E2-4%2A2500%29%29%2F%282%29 ALIGN=MIDDLE  ALT=\"x%5E2=%28225%2Bsqrt%28225%5E2-4%2A2500%29%29%2F%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=%28225%2Bsqrt%2840625%29%29%2F%282%29 ALIGN=MIDDLE  ALT=\"x%5E2=%28225%2Bsqrt%2840625%29%29%2F%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "----note: 40625=25*1625=25*25*65-------<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=%28225%2B25%2Asqrt%2865%29%29%2F%282%29 ALIGN=MIDDLE  ALT=\"x%5E2=%28225%2B25%2Asqrt%2865%29%29%2F%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "..<BR>\n" );
document.write( "Actually, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=%28225%2B201.556%29%2F%282%29 ALIGN=MIDDLE  ALT=\"x%5E2=%28225%2B201.556%29%2F%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  OR <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=%28225-201.556%29%2F%282%29 ALIGN=MIDDLE  ALT=\"x%5E2=%28225-201.556%29%2F%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=213.278 ALIGN=MIDDLE  ALT=\"x%5E2=213.278\"   DISABLED_style= \"max-width:90%; height:auto;\" >  OR  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=11.722 ALIGN=MIDDLE  ALT=\"x%5E2=11.722\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Finishing the value for x,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x=14.6%29 ALIGN=MIDDLE  ALT=\"highlight%28x=14.6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  OR  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x=3.4%29 ALIGN=MIDDLE  ALT=\"highlight%28x=3.4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >------ not really comfortable with this level of accuracy expected, but you can recompute if you wanted this one.\r<BR>\n" );
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document.write( "You can take care of the value of y. </SPAN>\n" );
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