document.write( "Question 823860: John was asked how old he is. He said in 2 years I will be twice as old as I was 5 years ago.\r
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Algebra.Com's Answer #495895 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You are correct. It is 12. Here's why\r
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\n" ); document.write( "\n" ); document.write( "Age 2 yrs in future = 2*(age in past 5 years ago)\r
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\n" ); document.write( "\n" ); document.write( "So the equation is \"x%2B2=2%28x-5%29\" and solving for it gives you...\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B2=2%28x-5%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B2=2x-10\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"x=2x-10-2\" Subtract \"2\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x-2x=-10-2\" Subtract \"2x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-x=-10-2\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-x=-12\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-12%29%2F%28-1%29\" Divide both sides by \"-1\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=12\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=12\"
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