document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=69633>Question 69633</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The two points(30,-25) and (50,65) determine a line </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49589 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE SLOPE OF A LINE THROUGH THESE TWO POINTS IS <BR>\n" );
document.write( "(Y2-Y2)/(X2-X1)<BR>\n" );
document.write( "(65+25)/(50-30)<BR>\n" );
document.write( "100/20<BR>\n" );
document.write( "5 IS THE SLOPE (m)<BR>\n" );
document.write( "NOW WE SUBSTITUTE ONE SET OF X & Y VALUES TO SOLVE FOR THR Y INTERCEPT(b) IN THE LINE EQUATION <BR>\n" );
document.write( "Y=mX+b<BR>\n" );
document.write( "-25=5*30+b<BR>\n" );
document.write( "-25=150+b<BR>\n" );
document.write( "B=-25-150<BR>\n" );
document.write( "b=-175 THUS THE EQUATRION FOR THIS LINE IS<BR>\n" );
document.write( "Y=5X-175 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );