document.write( "Question 69605: I am trying to use the addition and subtraction formulas to simplify sin(2pi-x). I am not sure where to begin. \n" ); document.write( "
Algebra.Com's Answer #49579 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
I am trying to use the addition and subtraction \r\n" );
document.write( "formulas to simplify\r\n" );
document.write( "\r\n" );
document.write( "\"+sin%282pi-+x%29+\". \r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "I am not sure where to begin.\r\n" );
document.write( "\r\n" );
document.write( "You have to know the formula\r\n" );
document.write( "\r\n" );
document.write( "\"+sin%28A-B%29+=+sin%28A%29cos%28B%29-cos%28A%29sin%28B%29\"\r\n" );
document.write( "\r\n" );
document.write( "Substitute \"2pi\" for A and \"x\" for B\r\n" );
document.write( "\r\n" );
document.write( "\"+sin%282pi-x%29+=+sin%282pi%29cos%28x%29-cos%282pi%29sin%28x%29\"\r\n" );
document.write( "\r\n" );
document.write( "Now use the fact that \r\n" );
document.write( "\r\n" );
document.write( "\"sin%282pi%29+=+0\" and \"cos%282pi%29+=+1\"\r\n" );
document.write( "\r\n" );
document.write( "Substituting those:\r\n" );
document.write( "\r\n" );
document.write( "\"+sin%282pi-x%29+=+%280%29cos%28x%29-%281%29sin%28x%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"%280%29cos%28x%29\" is just 0 and we can erase the 1:\r\n" );
document.write( "\r\n" );
document.write( "\"+sin%282pi-x%29+=+-sin%28x%29\"\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );