document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=823735>Question 823735</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A right triangle has an area of 60 ft(squared) and hypotenuse 17 ft. long.  What are the lengths of its other two sides?\r<BR>\n" );
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document.write( "So we know that:\r<BR>\n" );
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document.write( "x * y = 120\r<BR>\n" );
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document.write( "and \r<BR>\n" );
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document.write( "x(squared) + y (squared) = 17 (squared)\r<BR>\n" );
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document.write( "but if I substitute y = 120/x into the second equation, it quickly becomes crazy.  I have to multiply both sides by x (squared) to eliminate the fraction, and now I've got x to the 4th power to deal with and I get stuck. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #495750 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=495750\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Take u = x squared\r<BR>\n" );
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document.write( "Then\r<BR>\n" );
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document.write( "u + 120 squared / u  =  17(squared)\r<BR>\n" );
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document.write( "You can ask me more at : mthman@gmail.com\r<BR>\n" );
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document.write( "Thanks   </SPAN>\n" );
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