document.write( "Question 69475: Solve by completing the square:
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document.write( "x^2 + 2x - 8 = 0\r
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document.write( "Multiple choice:
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document.write( "a)-4, -2
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document.write( "b)-4, 2
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document.write( "c)4, -2
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document.write( "d)4,2\r
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document.write( "Thank you for helping! \n" );
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Algebra.Com's Answer #49574 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Solve by completing the square: \n" ); document.write( "x^2 + 2x - 8 = 0 \n" ); document.write( ": \n" ); document.write( "x^2 + 2x + ___ = 8; added 8 to both sides \n" ); document.write( ": \n" ); document.write( "Find the value that completes the square. \n" ); document.write( "Divide the coefficient of x by 2, and square that value: 2/2 = 1; 1^2 = 1 \n" ); document.write( ": \n" ); document.write( "x^2 + 2x + 1 = 8 + 1; we have to add 1 to both sides \n" ); document.write( ": \n" ); document.write( "(x + 1)^2 = 9; Note that (x+1)^2 is same as:(x+1)*(x+1), which = x^2 + 2x + 1) \n" ); document.write( ": \n" ); document.write( "Find the square root of both sides: \n" ); document.write( " x + 1 = +/- Sqrt(9) \n" ); document.write( ": \n" ); document.write( "x = -1 +/- Sqrt(9) \n" ); document.write( ": \n" ); document.write( "x = -1 + 3 \n" ); document.write( "x = +2 \n" ); document.write( "and \n" ); document.write( "x = -1 - 3 \n" ); document.write( "x = -4 \n" ); document.write( ": \n" ); document.write( "Can you do this now? \n" ); document.write( " |