document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=823676>Question 823676</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Liam is planning a three hour trip down the East River and back to his starting point. He knows that he can paddle in still water at 3 mi/h and that the rate of the current is 2 mi/h. How much time can he spend going downstream? How far downstream can he travel? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #495695 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=495695\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the distance distance downstream be x\r<BR>\n" );
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document.write( "upstream speed = 3-1=2 mph\r<BR>\n" );
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document.write( "downstream speed = 3+2 = 5 mph\r<BR>\n" );
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document.write( "time downstream + time upstream = 3\r<BR>\n" );
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document.write( "x/2 +x/5 =3\r<BR>\n" );
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document.write( "multiply by 10\r<BR>\n" );
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document.write( "5x+2x=30<BR>\n" );
document.write( "7x=30\r<BR>\n" );
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document.write( "x= 30/7 = 4.3 miles\r<BR>\n" );
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document.write( "time down stream = 4.3/5<BR>\n" );
document.write( "=0.86 hours<BR>\n" );
document.write( "or 52 minutes </SPAN>\n" );
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