document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=823638>Question 823638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is three more than twice the width.  The perimeter is 78 centimeters.  What is the width in centimeters of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #495692 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=495692\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = width<BR>\n" );
document.write( "2x + 3 = length {the length is 3 more than twice the width}\r<BR>\n" );
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document.write( "Perimeter of a rectangle is 2(width) + 2(length}\r<BR>\n" );
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document.write( "2x + 2(2x + 3) = 78 {substituted given information into perimeter formula}<BR>\n" );
document.write( "2x + 4x + 6 = 78 {used distributive property}<BR>\n" );
document.write( "6x + 6 = 78 {combined like terms}<BR>\n" );
document.write( "6x = 72 {subtracted 6 from each side}<BR>\n" );
document.write( "x = 12 {divided each side by 6}\r<BR>\n" );
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document.write( "width = 12 cm<BR>\n" );
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