document.write( "Question 69586: What is the area of a rectangle that has a perimeter of 47 mm and a length of 18.5 mm? \n" ); document.write( "
Algebra.Com's Answer #49568 by bucky(2189)\"\" \"About 
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To find the perimeter (P) of a rectangle you need to add 2 times the length (L) to 2 times the width (W) of the rectangle. In equation form this is written:\r
\n" ); document.write( "\n" ); document.write( "\"2L+%2B+2W+=+P\"\r
\n" ); document.write( "\n" ); document.write( "You are given that P is 47mm and L is 18.5mm. Substitute these values into the equation to get:\r
\n" ); document.write( "\n" ); document.write( "\"2%2A18.5+%2B+2W+=+47\"\r
\n" ); document.write( "\n" ); document.write( "Multiply out the 2*18.5 and the equation becomes:\r
\n" ); document.write( "\n" ); document.write( "\"37+%2B+2W+=+47\"\r
\n" ); document.write( "\n" ); document.write( "Subtract 37 from both sides to remove it from the left side of the equation. The result is:\r
\n" ); document.write( "\n" ); document.write( "\"2W+=+10\"\r
\n" ); document.write( "\n" ); document.write( "Finally, divide both sides by 2 and you find that:\r
\n" ); document.write( "\n" ); document.write( "W = 5 mm.\r
\n" ); document.write( "\n" ); document.write( "Then recognize that the area of a rectangle is found by multiplying its length times its width. You were given that the length was 18.5 mm and you found that the width was 5 mm. Multiplying these two together results in an area (A) equal to:\r
\n" ); document.write( "\n" ); document.write( "\"A+=+18.5%2A5\"\r
\n" ); document.write( "\n" ); document.write( "which multiplies out to:\r
\n" ); document.write( "\n" ); document.write( "\"A+=+92.5\" \r
\n" ); document.write( "\n" ); document.write( "and the units of the answer are square mm\r
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