document.write( "Question 823648: Amy can clean the house twice as fast as Thomas. Together, they can clean the house in 6 hours. How long would it take each of them working alone to clean the house? \n" ); document.write( "
Algebra.Com's Answer #495662 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Amy can clean the house twice as fast as Thomas. Together, they can clean the house in 6 hours. How long would it take each of them working alone to clean the house? \n" ); document.write( "------ \n" ); document.write( "Thomas:: time = 2x hr/job ; rate = 1/(2x) job/hr \n" ); document.write( "Amy:::: time = x hr/job ; rate = 1/x job/hr \n" ); document.write( "Together: time = 6 hr/job ; rate = 1/6 job/hr \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "rate + rate = together rate \n" ); document.write( "1/(2x) + 1/x = 1/6 \n" ); document.write( "Multiply thru by 6x to get: \n" ); document.write( "3 + 6 = x \n" ); document.write( "x = 9 (Amy's time to do the job alone) \n" ); document.write( "2x = 18 (Thomas's time to do the job alone \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " |