document.write( "Question 823567: give the zeros write a cubic polynomial in standard form. x= -2, 1, 4 \n" ); document.write( "
Algebra.Com's Answer #495606 by jim_thompson5910(35256)\"\" \"About 
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x= -2, 1, 4\r
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\n" ); document.write( "\n" ); document.write( "x= -2, x = 1, x = 4\r
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\n" ); document.write( "\n" ); document.write( "x+2=0, x-1=0, x-4=0\r
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\n" ); document.write( "\n" ); document.write( "(x+2)(x-1)(x-4)=0\r
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\n" ); document.write( "\n" ); document.write( "(x+2)(x^2-4x-1x+4)=0\r
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\n" ); document.write( "\n" ); document.write( "(x+2)(x^2-5x+4)=0\r
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\n" ); document.write( "\n" ); document.write( "x(x^2-5x+4)+2(x^2-5x+4)=0\r
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\n" ); document.write( "\n" ); document.write( "x^3-5x^2+4x+2x^2-10x+8=0\r
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\n" ); document.write( "\n" ); document.write( "x^3-3x^2-6x+8=0\r
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\n" ); document.write( "\n" ); document.write( "Final Answer: \"x%5E3-3x%5E2-6x%2B8\"
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