document.write( "Question 823533: The hypotenuse of a triangle is 17 cm. The length of one leg is 1 cm less than twice the length of the other. Find the length of each leg. \n" ); document.write( "
Algebra.Com's Answer #495578 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi
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document.write( "The hypotenuse of a triangle is 17 cm. 
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document.write( "The length of one leg is 1 cm less than twice the length of the other\"highlight_green%28x%29\". 
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document.write( "Find the length of each leg: \"highlight_green%28x%29\"  and \"highlight_green%282x-1%29\"
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document.write( "Applying the Pythagorean Theorem
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document.write( "  x^2 + (2x-1)^2 = 17^2 =289
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document.write( "   x^2 + 4x^2 - 4x + 1 = 289
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document.write( "         5x^2 - 4x - 288 = 0 
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document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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document.write( "\"x+=+%284+%2B-+sqrt%285776+%29%29%2F%2810%29+\"
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document.write( "\"x+=+%284+%2B-+76%29%2F10+\"
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document.write( "  x = -7.5, 8  (tossing out negative solution for unit measure
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document.write( "  x = 8cm  and the other leg is 15cm         \"highlight_green%282x-1%29\"
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document.write( "CHECKING our answer***
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document.write( "  64 + 225 = 289 \n" );
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