document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=823474>Question 823474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 15-foot piece of string is cut into two pieces so that the longer piece is 3 feet longer than twice the shorter piece. if the shorter piece is x feet long, find the lengths of both pieces </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #495530 by </B><A HREF=/tutors/aboutme.mpl?userid=faceoff57><B>faceoff57(108)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=faceoff57><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=faceoff57><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=495530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a 15-foot piece of string is cut into two pieces so that the longer piece is 3 feet longer than twice the shorter piece. if the shorter piece is x feet long, find the lengths of both pieces<BR>\n" );
document.write( "L = 3 + 2x<BR>\n" );
document.write( "S = x<BR>\n" );
document.write( "X + (3 + 2x) = 15<BR>\n" );
document.write( "X + 3 + 2x = 15<BR>\n" );
document.write( "3x + 3 = 15<BR>\n" );
document.write( "3x = 15 - 3<BR>\n" );
document.write( "3x = 12<BR>\n" );
document.write( "X = 4 <BR>\n" );
document.write( "3 + 2x =<BR>\n" );
document.write( "3 + 2(4) =<BR>\n" );
document.write( "3 + 8 = 11<BR>\n" );
document.write( "Short piece is 4 feet<BR>\n" );
document.write( "Long piece is 11 feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );