document.write( "Question 823458: Suppose tom has 23 coins totaling 3.80. If he has only dimes and quarters, how many of each type does he have \n" ); document.write( "

Algebra.Com's Answer #495528 by richwmiller(17219) $\"\"$ $\"About$

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at least three are dimes
\n" ); document.write( "so we have 20 coins with a total of 3.50
\n" ); document.write( "if the rest are all quarters then there would be 4*3+2=14 but we need 20
\n" ); document.write( "so we are 6 short
\n" ); document.write( "we must have dimes in multiples of 5
\n" ); document.write( "12 q + 5 d=3.50 but only 17 coins
\n" ); document.write( "10q +10 dimes=3.50 with 20 coins
\n" ); document.write( "10 q +13 dimes total\r
\n" ); document.write( "\n" ); document.write( "algebraic solution
\n" ); document.write( "d+q=23
\n" ); document.write( "25q+10d=380
\n" ); document.write( "d=23-q
\n" ); document.write( "25q+10*(23-q)=380
\n" ); document.write( "25q+230-10q=380
\n" ); document.write( "15q=150
\n" ); document.write( "q=10
\n" ); document.write( "d=13\r
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