document.write( "Question 823438: A rectangular area is enclosed with fencing where the width is 5 feet less than the length. If the area is 300 square feet, what is the width? \n" ); document.write( "
Algebra.Com's Answer #495506 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "A rectangular area is enclosed with fencing
\n" ); document.write( "where the width is 5 feet less than the length\"highlight_green%28x%29\". width is \"highlight_green%28x-5%29\".
\n" ); document.write( "If the area is 300 square feet, what is the width?
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\n" ); document.write( " A = lw = x(x-5) = 300ft^2
\n" ); document.write( " x^2 - 5x - 300 = 0
\n" ); document.write( " (x +15)(x-20) = 0 |tossing out the negative solution for unit measure
\n" ); document.write( " x = 20ft, the length and the width is 15ft \"highlight_green%28x-5%29\". \r
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