document.write( "Question 823381: Find the equation, in standard form, of the line perpendicular to -5x+3y=3 that passes through the points (-8,-9). Write the equation in standard form.
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Algebra.Com's Answer #495481 by mananth(16946)\"\" \"About 
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-5 x + 3 y = 3
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "3 y = 5 x + 3
\n" ); document.write( "Divide by 3
\n" ); document.write( " y = 5/ 3 x + 1
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = 5/3
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal - 3/5
\n" ); document.write( "Because m1*m2 =-1
\n" ); document.write( "The slope of the required line will be - 3/5
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\n" ); document.write( "m= - 3/5 ,point ( -8 , -9 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "-9 = 24/ 5 + b
\n" ); document.write( "b= -69/5
\n" ); document.write( "m= - 3/5
\n" ); document.write( "The required equation is y = - 3/ 5 x + -69/ 5 \r
\n" ); document.write( "\n" ); document.write( "multiply by 5
\n" ); document.write( "5y=-3x-69
\n" ); document.write( "3x+5y=-69
\n" ); document.write( "m.ananth@hotmail.ca
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