document.write( "Question 823330: using cos3x= 4cos^3x -3cosx
\n" ); document.write( "find the general solution for cos3x+2cosx=0\r
\n" ); document.write( "\n" ); document.write( "Soln:
\n" ); document.write( " cos3x+2cosx=0 ............(1)
\n" ); document.write( "or, 4cos^x-3cosx+2cosx=0 {put the given value of cos3x=4cos^x-3cosx in the
\n" ); document.write( " above equation (1)}
\n" ); document.write( "or, 4cos^3x-cosx=0
\n" ); document.write( "or, cosx(4cos^2x-1)=0
\n" ); document.write( "now we get, cosx=0 and 4cos^2x-1=0
\n" ); document.write( "solve these two equations separately to get the solution.
\n" ); document.write( "taking cosx=0
\n" ); document.write( "or, cosx=cos90 ,we know the value of cos 90 is zero so put cos90 for 0
\n" ); document.write( "or, x=90 degree
\n" ); document.write( "now, taking 4cos^2x-1=0
\n" ); document.write( "or, cos^2x=1/4
\n" ); document.write( "or, cosx=+1/2 and cosx=-1/2
\n" ); document.write( "or, cosx=cos60 and cosx=cos120
\n" ); document.write( "or, x=60 degree and x=120 degree
\n" ); document.write( "hence, the results are x= 90,60,120 degrees.
\n" ); document.write( "

Algebra.Com's Answer #495468 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
using cos3x= 4cos^3x -3cosx
\n" ); document.write( "find the general solution for
\n" ); document.write( "cos3x+2cosx=0
\n" ); document.write( "interval:[0,2π]
\n" ); document.write( "\"4cos%5E3%28x%29-3cos%28x%29%2B2cos%28x%29=0\"
\n" ); document.write( "..
\n" ); document.write( "\"4cos%5E3%28x%29-cos%28x%29=0\"
\n" ); document.write( "..
\n" ); document.write( "\"cos%28x%29%284cos%5E2%28x%29-1%29=0\"
\n" ); document.write( "..
\n" ); document.write( "cos(x)=0
\n" ); document.write( "x=π/2,3π/2
\n" ); document.write( "..
\n" ); document.write( "4cos^2(x)-1=0
\n" ); document.write( "cos^2(x)=1/4
\n" ); document.write( "cosx=±√(1/4)=±1/2
\n" ); document.write( "x=π/3,2π/3,4π/3,5π/3
\n" ); document.write( "
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