document.write( "Question 823330: using cos3x= 4cos^3x -3cosx
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document.write( "find the general solution for cos3x+2cosx=0\r
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document.write( "Soln:
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document.write( " cos3x+2cosx=0 ............(1)
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document.write( "or, 4cos^x-3cosx+2cosx=0 {put the given value of cos3x=4cos^x-3cosx in the
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document.write( " above equation (1)}
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document.write( "or, 4cos^3x-cosx=0
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document.write( "or, cosx(4cos^2x-1)=0
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document.write( "now we get, cosx=0 and 4cos^2x-1=0
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document.write( "solve these two equations separately to get the solution.
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document.write( "taking cosx=0
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document.write( "or, cosx=cos90 ,we know the value of cos 90 is zero so put cos90 for 0
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document.write( "or, x=90 degree
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document.write( "now, taking 4cos^2x-1=0
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document.write( "or, cos^2x=1/4
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document.write( "or, cosx=+1/2 and cosx=-1/2
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document.write( "or, cosx=cos60 and cosx=cos120
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document.write( "or, x=60 degree and x=120 degree
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document.write( "hence, the results are x= 90,60,120 degrees. \n" );
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Algebra.Com's Answer #495468 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! using cos3x= 4cos^3x -3cosx \n" ); document.write( "find the general solution for \n" ); document.write( "cos3x+2cosx=0 \n" ); document.write( "interval:[0,2π] \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "cos(x)=0 \n" ); document.write( "x=π/2,3π/2 \n" ); document.write( ".. \n" ); document.write( "4cos^2(x)-1=0 \n" ); document.write( "cos^2(x)=1/4 \n" ); document.write( "cosx=±√(1/4)=±1/2 \n" ); document.write( "x=π/3,2π/3,4π/3,5π/3 \n" ); document.write( " |