document.write( "Question 69542: Arnold had $1.70 in dimes and quarters. HE had 3 more dimes than quarter. How many of each coin did he have? \n" ); document.write( "
Algebra.Com's Answer #49537 by tanimachatterjee(60)\"\" \"About 
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suppose Arnold had x dimes and y quarters
\n" ); document.write( " value of x dimes = 10x cents
\n" ); document.write( " y quarters =25y cents
\n" ); document.write( " tolal value =10x+25y cents
\n" ); document.write( " by the problem 10x+ 25y=170..............(1)
\n" ); document.write( " and x=y+3....(2)\r
\n" ); document.write( "\n" ); document.write( "replacing the value of x in (1) we have 10(y+3) +25y=170
\n" ); document.write( " or 10y +30 +25y=170
\n" ); document.write( " or 35y= 170-30=140
\n" ); document.write( " y= 4\r
\n" ); document.write( "\n" ); document.write( " x=y+3
\n" ); document.write( " = 4+3
\n" ); document.write( " =7\r
\n" ); document.write( "\n" ); document.write( "Arnold had 7 dimes and 4 quarters\r
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