document.write( "Question 69453: The preimeter of a rectangular garden is 40 feet. The width is 2 feet more than 1/2 the length. Find the length and width? \n" ); document.write( "
Algebra.Com's Answer #49535 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "Let x= length\r
\n" ); document.write( "\n" ); document.write( "Then (x/2)+2 = width\r
\n" ); document.write( "\n" ); document.write( "Perimeter= 2L+2W\r
\n" ); document.write( "\n" ); document.write( "40=2x+2(x/2+2) get rid of parens\r
\n" ); document.write( "\n" ); document.write( "40=2x+x+4 subtract 4 from both sides\r
\n" ); document.write( "\n" ); document.write( "40-4=3x
\n" ); document.write( "36=3x\r
\n" ); document.write( "\n" ); document.write( "x=12 ft------------------------length\r
\n" ); document.write( "\n" ); document.write( "x/2+2=12/2+2=6+2=8 ft------------------------------width\r
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\n" ); document.write( "\n" ); document.write( "ck\r
\n" ); document.write( "\n" ); document.write( "2L+2W=40\r
\n" ); document.write( "\n" ); document.write( "24+16=40
\n" ); document.write( "40=40\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps -----ptaylor
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