document.write( "Question 822332: How do you put this conic section into standard form? I know it's a hyperbola.\r
\n" ); document.write( "\n" ); document.write( "6y^2+24y-x^2-36=0
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Algebra.Com's Answer #495326 by lwsshak3(11628)\"\" \"About 
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How do you put this conic section into standard form? I know it's a hyperbola.
\n" ); document.write( "6y^2+24y-x^2-36=0
\n" ); document.write( "complete the square:
\n" ); document.write( "6(y^2+4y+4)-x^2-36=0
\n" ); document.write( "6(y+2)^2-x^2=36+24=60
\n" ); document.write( "\"%28y%2B2%29%5E2%2F10-x%5E2%2F60=1\"
\n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis and center at (0,-2).
\n" ); document.write( "Its standard form: \"%28y-h%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1\", (h,k)=(x,y) coordinates of center.
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