document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=69530>Question 69530</A>: <I><SPAN STYLE=\"word-break: break-all;\">   Hi, \r<BR>\n" );
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document.write( "  I need to find 3 solution for 6x-3/2y-12=12\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49532 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6x+-+%283%2F2%29y+-+12+=+12 ALIGN=MIDDLE  ALT=\"6x+-+%283%2F2%29y+-+12+=+12\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Let's begin by simplifying the equation.  Let's multiply everything by 2 to get rid of the denominator in the y-term.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12x+-+3y+-+24+=+24 ALIGN=MIDDLE  ALT=\"12x+-+3y+-+24+=+24\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now add 24 to both sides to move the -24 to the right side of the equal sign.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12x+-+3y+=+48 ALIGN=MIDDLE  ALT=\"12x+-+3y+=+48\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now all you have to do is to assume a value for x and find a corresponding value for y.  For example, let's assume x = 1.  The equation becomes:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2812%2A1%29+-+3y+=+48 ALIGN=MIDDLE  ALT=\"%2812%2A1%29+-+3y+=+48\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "and this becomes:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12+-+3y+=+48 ALIGN=MIDDLE  ALT=\"12+-+3y+=+48\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Subtract 12 from both sides to get:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+-3y+=+36 ALIGN=MIDDLE  ALT=\"+-3y+=+36\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "and by dividing both sides by -3 you find that y = -12\r<BR>\n" );
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document.write( "In the Cartesian point form (x,y) this means that (1, -12) is an answer.\r<BR>\n" );
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document.write( "You can find other answers using the same process as above.  For example, if you assume x = 2 and substitute that into the equation, you should find that y = -8 so that (2, -8) is another solution.  And if you assume x = 4, you should find that y must = 0 so that (4, 0) is another solution.\r<BR>\n" );
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document.write( "Another way to look at this is graphically.  Return to the equation:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12x+-+3y+=+48 ALIGN=MIDDLE  ALT=\"12x+-+3y+=+48\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "First set x = 0 and the result will be y = 48/-3 = -16.  Plot the point (0, -16) on the graph.  Then let y = 0 and the result will be x = 48/12 = 4.  Plot the point (4, 0) on the graph.  Draw a line through those two points and extend the line in both directions.  Any Cartesian point on that line will give you a set of x and y values that satisfies the equation.  There are any number (an infinite amount) of values that will answer the problem.\r<BR>\n" );
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document.write( "Hope this helps you understand the problem a little better.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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