document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=823023>Question 823023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a wire 200 cm long is bent to form a rectangle. the length of the rectangle is 3 cm longer than the width . find the dimensions of the rectangle  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #495210 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=495210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we are given that the perimeter (P) of the rectangle is 200 cm.  We know that <BR>\n" );
document.write( "P = 2*length (L) + 2 (W), let x be W, then<BR>\n" );
document.write( "200 = 2*(x+3) + 2*x<BR>\n" );
document.write( "200 = 2x +6 +2x<BR>\n" );
document.write( "4x = 194<BR>\n" );
document.write( "x = 48 1/2 cm<BR>\n" );
document.write( "width is 48 1/2 cm and length is 51 1/2 cm<BR>\n" );
document.write( "check the answer<BR>\n" );
document.write( "200 = 2 * (48 1/2 +3) + 2 * 48 1/2<BR>\n" );
document.write( "200 = 103 + 97<BR>\n" );
document.write( "200 = 200<BR>\n" );
document.write( "answer checks\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );