document.write( "Question 823002: solve for theta where 0\n" ); document.write( "I) 2sin2theta= -1 \n" ); document.write( "
Algebra.Com's Answer #495199 by jsmallt9(3758)\"\" \"About 
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Note: After seeing your thank you note I came back to my solution and checked. I'm sorry to say that I was wrong about the reference angle. A reference angle of \"pi%2F6\" not \"pi%2F3\" has a sin of 1/2. Everything else was correct. The problem below has been redone using the proper reference angle.

\n" ); document.write( "\"2sin%282theta%29+=+-1\"
\n" ); document.write( "First isolate the function and its argument by dividing both sides by 2:
\n" ); document.write( "\"sin%282theta%29+=+-1%2F2\"

\n" ); document.write( "We should recognize that 1/2 (positive or negative) is a special angle value for sin. Without our calculator we should know that a 1/2 for sin indicates a reference angle of \"pi%2F6\". Since the 1/2 is negative and since sin is negative in the 3rd and 4th quadrants we should get the following general solution equations (for 2 theta):
\n" ); document.write( "\"2theta+=+pi%2Bpi%2F6%2B2pi%2An\" (for the 3rd quadrant)
\n" ); document.write( "\"2theta+=+-pi%2F6%2B2pi%2An\" (for the 4th quadrant)
\n" ); document.write( "The first equation will simplify:
\n" ); document.write( "\"2theta+=+7pi%2F6%2B2pi%2An\"
\n" ); document.write( "\"2theta+=+-pi%2F6%2B2pi%2An\"
\n" ); document.write( "Dividing both sides of both equations by 2:
\n" ); document.write( "\"theta+=+7pi%2F12%2Bpi%2An\"
\n" ); document.write( "\"theta+=+-pi%2F12%2Bpi%2An\"

\n" ); document.write( "Now we try various integer values for n as we search for specific solutions which are in the specified interval.
\n" ); document.write( "From \"theta+=+7pi%2F12%2Bpi%2An\":
\n" ); document.write( "If n = 0 then \"theta+=+7pi%2F12\"
\n" ); document.write( "If n = 1 then \"theta+=+19pi%2F12\"
\n" ); document.write( "If n = 2 (or larger) then \"theta\" is too large for the interval
\n" ); document.write( "If n = -1 (or smaller) then \"theta\" is too small for the interval
\n" ); document.write( "From \"theta+=+-pi%2F12%2Bpi%2An\":
\n" ); document.write( "If n = 0 (or smaller) then \"theta\" is too small for the interval
\n" ); document.write( "If n = 1 then \"theta+=+11pi%2F12\"
\n" ); document.write( "If n = 2 then \"theta+=+23pi%2F12\"
\n" ); document.write( "If n = 3 (or larger) then \"theta\" is too large for the interval

\n" ); document.write( "So the only solutions in the specified interval are: \"7pi%2F12\", \"19pi%2F12\", \"11pi%2F12\" and \"23pi%2F12\"
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