document.write( "Question 822869: Find the vertex of the parabola y^2 +8x - 6y +1=0
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Algebra.Com's Answer #495173 by lwsshak3(11628)\"\" \"About 
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Find the vertex of the parabola y^2 +8x - 6y +1=0
\n" ); document.write( "complete the square:
\n" ); document.write( "(y^2-6y+9)+8x=-1+9
\n" ); document.write( "(y-3)^2=-8x+8=-8(x-1)
\n" ); document.write( "(y-3)^2=-8(x-1)
\n" ); document.write( "This is a parabola that opens leftward.
\n" ); document.write( "Its basic equation:(y-k)^2=-4p(x-h), (h,k)=(x,y) coordinates of vertex
\n" ); document.write( "For given parabola:
\n" ); document.write( "vertex(1,3)
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