document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=822768>Question 822768</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a sail boat goes downstream for an hour and upstream for 3 hours.  a motorboat goes downstream 2 hours and upsteam for 1 hour.  the river's current speed is 5 mph.  the distance traveled by both, not each, boats upstream is 205 miles and downstream is 200 miles  find the speed of each boat. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #495142 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=495142\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a sail boat goes downstream for an hour and upstream for 3 hours.<BR>\n" );
document.write( " a motorboat goes downstream 2 hours and upsteam for 1 hour.<BR>\n" );
document.write( " the river's current speed is 5 mph.<BR>\n" );
document.write( " the distance traveled by both, not each, boats upstream is 205 miles and downstream is 200 miles find the speed of each boat.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Let s = still water speed of the sailboat<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(s+5) = sailboat speed downstream<BR>\n" );
document.write( "and<BR>\n" );
document.write( "(s-5)= sailboat speed upstream<BR>\n" );
document.write( ":<BR>\n" );
document.write( "let m = motorboat speed in still water<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(m+5) = motorboat speed down stream<BR>\n" );
document.write( "and<BR>\n" );
document.write( "(m-5) = it's speed upstream<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Down stream dist equation<BR>\n" );
document.write( "1(s+5) + 2(m+5) = 200<BR>\n" );
document.write( "s + 5 + 2m + 10 = 200<BR>\n" );
document.write( "s + 2m = 200 - 15<BR>\n" );
document.write( "s + 2m = 185<BR>\n" );
document.write( "s = (185-2m); use for substitution<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Upstream dist equation<BR>\n" );
document.write( "3(s-5) + 1(m-5) = 205<BR>\n" );
document.write( "3s - 15 + m - 5 = 205<BR>\n" );
document.write( "3s + m = 205 + 20<BR>\n" );
document.write( "3s + m = 225<BR>\n" );
document.write( "Replace s with (185-2m)<BR>\n" );
document.write( "3(185-2m) + m = 225<BR>\n" );
document.write( "555 - 6m + m = 225<BR>\n" );
document.write( "-5m = 225 - 555<BR>\n" );
document.write( "-5m = -330<BR>\n" );
document.write( "m = -330/-5<BR>\n" );
document.write( "m = +66 mph is the motor boat speed in still water<BR>\n" );
document.write( ":<BR>\n" );
document.write( "s = 185 - 2(66)<BR>\n" );
document.write( "s = 53 mph is the sailboat speed, impossible but there it is\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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