document.write( "Question 822729: Figure 1 represents a conical container with a diameter of 120cm and a depth of 140cm. It is filled with water to a depth of 60cm.
\n" ); document.write( "a) Find the volume of water in the container. (SOLVED)
\n" ); document.write( "b) Find the surface area of container in contact with the water. (SOLVED)
\n" ); document.write( "c)The container in Fig. 1 is inverted so that the water is now at the base of the cone with height h cm. Calculate the value of h.
\n" ); document.write( "* Fig. 1's cone is inverted with the tip facing down , fig
\n" ); document.write( " 2's cone is the upright one with th base on the ground.\r
\n" ); document.write( "\n" ); document.write( "Appreciate your help as this is the last question for my holiday assignment. Thanks !
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Algebra.Com's Answer #495127 by KMST(5328)\"\" \"About 
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The volume of a cone can be calculated as \"pi%2AR%5E2%2AH%2F3\" ,
\n" ); document.write( "where \"R\" is the radius of the base and \"H\" is the height of the cone.
\n" ); document.write( "Inside that conical container,
\n" ); document.write( "there is a cone of water at first,
\n" ); document.write( "with air above it.
\n" ); document.write( "When the container is inverted,
\n" ); document.write( "there is a cone of air on top,
\n" ); document.write( "and water below it.
\n" ); document.write( "All the cones are similar.
\n" ); document.write( "The radius of the conical container, \"120cm%2F2=60cm\" is
\n" ); document.write( "\"60cm%2F%22140+cm%22=3%2F7\" of the height.
\n" ); document.write( "\"R%2FH=3%2F7\" <---> \"R=3H%2F7\"
\n" ); document.write( "The ratio is the same for all the other similar cones.
\n" ); document.write( "Their volume is
\n" ); document.write( "
\n" ); document.write( "The volume of the conical container, in cubic centimeters, is
\n" ); document.write( "\"pi%2A3%2A140%5E3%2F49=168000pi=about527788\" .
\n" ); document.write( "The volume of water in the container, in cubic centimeters, is
\n" ); document.write( "\"pi%2A3%2A60%5E3%2F49=648000pi%2F49=about41546\" .
\n" ); document.write( "The volume of air in the container, in cubic centimeters, is
\n" ); document.write( "\"168000pi-648000pi%2F49=7584000pi%2F49=about486242\" .
\n" ); document.write( "We can find the height, \"H\", of the cone of air, in cm:
\n" ); document.write( "\"pi%2A3%2AH%5E3%2F49=7584000pi%2F49\"
\n" ); document.write( "\"3%2AH%5E3=7584000\"
\n" ); document.write( "\"H%5E3=7584000%2F3\"
\n" ); document.write( "\"H%5E3=2528000\"
\n" ); document.write( "\"H=root%283%2C2528000%29=about136.2\"
\n" ); document.write( "Once the cone is standing on its base, there is a cone of air inside the tip of the container that has a height of \"136.2cm\" .
\n" ); document.write( "If \"136.2cm\" at the tip of the cone are air, the remaining \"highlight%28h=3.8cm%29\" at the base of the cone are full of water.
\n" ); document.write( "\"140cm-136.2cm=3.8cm\"
\n" ); document.write( "
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