document.write( "Question 822853: When x^4-8x^2-9 is factored as completely as possible, which of the following is a prime factor ?\r
\n" ); document.write( "\n" ); document.write( "a) (x+1)
\n" ); document.write( "b) (x^2-9)
\n" ); document.write( "c) (x+1)^2
\n" ); document.write( "d) (x+3)
\n" ); document.write( "e) (x^2+9)\r
\n" ); document.write( "\n" ); document.write( "I don't understand it and can someone explain how to go about doing this problem?
\n" ); document.write( "Thanks, much is appreciated.
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Algebra.Com's Answer #495116 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The goal is to factor. So we must find two numbers that multiply to -9 (last term) AND add to -8 (middle coefficient). These two numbers are +1 and -9, so we break up the middle term -8x^2 into +1x^2 - 9x^2 and we factor by grouping like so...\r
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\n" ); document.write( "\n" ); document.write( "x^4-8x^2-9\r
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\n" ); document.write( "\n" ); document.write( "x^4+x^2-9x^2-9\r
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\n" ); document.write( "\n" ); document.write( "(x^4+x^2)+(-9x^2-9)\r
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\n" ); document.write( "\n" ); document.write( "x^2(x^2+1)+(-9x^2-9)\r
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\n" ); document.write( "\n" ); document.write( "x^2(x^2+1)-9(x^2+1)\r
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\n" ); document.write( "\n" ); document.write( "(x^2-9)(x^2+1)\r
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\n" ); document.write( "\n" ); document.write( "(x^2-3^2)(x^2+1)\r
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\n" ); document.write( "\n" ); document.write( "(x-3)(x+3)(x^2+1) ... use the difference of squares rule here\r
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\n" ); document.write( "\n" ); document.write( "x^4-8x^2-9\r
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\n" ); document.write( "\n" ); document.write( "completely factors to\r
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\n" ); document.write( "\n" ); document.write( "(x-3)(x+3)(x^2+1)\r
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\n" ); document.write( "\n" ); document.write( "So the final answer (that they want) is d) (x+3)
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