document.write( "Question 822808: Find two positive even integers whose product is 48
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Algebra.Com's Answer #495095 by jim_thompson5910(35256)\"\" \"About 
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Let x be the first integer.\r
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\n" ); document.write( "\n" ); document.write( "So x+2 is the next consecutive even integer\r
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\n" ); document.write( "\n" ); document.write( "x*(x+2) = 48\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 2x = 48\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 2x - 48 = 0\r
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\n" ); document.write( "\n" ); document.write( "(x+8)(x-6) = 0\r
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\n" ); document.write( "\n" ); document.write( "x+8 = 0 or x-6 = 0\r
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\n" ); document.write( "\n" ); document.write( "x = -8 or x = 6\r
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\n" ); document.write( "\n" ); document.write( "Since we only want positive even integers, this means that we toss out x = -8 and focus on x = 6\r
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\n" ); document.write( "\n" ); document.write( "x = 6 ----> x+2 = 6+2 = 8\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the two numbers are 6 and 8
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