document.write( "Question 822803: Joy and Glenn each went on a bike ride.\r
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document.write( " - Joy rode at a rate of 0.05 miles per minute. \r
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document.write( " -Glenn rode at a rate .2 miles per minute.. \r
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document.write( " -Glenn started riding 8 minutes after Joy.\r
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document.write( "How long after Joy starting riding, in minutes, did it take for Glenn to catch up to Joy? \n" );
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Algebra.Com's Answer #495094 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! .4=8*.05 \n" ); document.write( ".4/.15= 2 2/3 minutes to catch up.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |