document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=822569>Question 822569</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sum of present age of 10 student's is 100 year. what is the average age of students 5 year ago?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #494995 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=494995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Five years ago each student would be five years younger. IOW, each student's age would be a smaller by 5 years. So the sum of the student's ages five years ago would be 10*5 less than their sum today. This makes the sum of the ages five years ago 100 - 50 or 50.<br><BR>\n" );
document.write( "The average age five years ago would then be 50/10 or 5. </SPAN>\n" );
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