document.write( "Question 822584: A, B and C can do a piece of work in 12 days. A alone takes twice as long as B and C together, and B takes three times as long as A and C together. In what time A will do the work alone? \n" ); document.write( "
Algebra.Com's Answer #494967 by richwmiller(17219) You can put this solution on YOUR website! 1/a+1/b+1/c=1/12, \n" ); document.write( "1/b+1/c=1/(x), \n" ); document.write( "x=a/2, \n" ); document.write( "1/a+1/c=1/(y), \n" ); document.write( "y=b/3 \n" ); document.write( "a = 36, b = 48, c = 144/5, x (b+c together) = 18, y (a+c together) = 16 \n" ); document.write( "check \n" ); document.write( "36=2*18 \n" ); document.write( "48=3*16 \n" ); document.write( "ok\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |