document.write( "Question 822582: The present age of a man is 7x years and that of his son is (2x-1) years. When the man was (x square - 5) years old, his son was (x+1) years. Then present age of his son is- \n" ); document.write( "
Algebra.Com's Answer #494964 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 7x-(2x-1)=x^2-5-(x+1) \n" ); document.write( "7x-2x+1=x^2-5-x-1 \n" ); document.write( "5x+1=x^2-x-6 \n" ); document.write( "x^2-6x-7=0 \n" ); document.write( "(x-7)*(x+1)=0 \n" ); document.write( "x=7 \n" ); document.write( "father is 49 \n" ); document.write( "son is 14-1=13 \n" ); document.write( "check \n" ); document.write( "49-5=44 \n" ); document.write( "8=13-5 \n" ); document.write( "ok\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |