document.write( "Question 822560: Find the equation ,in the form y = ax^2 + bx + c,of the parabola which passes through the points(-3,0) and (1,-16). \n" ); document.write( "
Algebra.Com's Answer #494956 by Alomelo(2)\"\" \"About 
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For (-3,0)
\n" ); document.write( "we write 0=(-3)^2+b(-3)+C, So, 3b-c=9........(i)\r
\n" ); document.write( "\n" ); document.write( "and for(1,-16), So b+c=-17......................(ii)
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\n" ); document.write( "\n" ); document.write( "So (i)+(ii) we get b=-2
\n" ); document.write( "So put this into equation(ii) we get c=-15
\n" ); document.write( " so ultimetly the equation is: y=x^2-2x-15.
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